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Chi-square Degrees of Freedom

Linear 7.96 on 1 p=.005
Lack of fit 0.29 on 1 p=.130

Total 8.25 on 2 (Pearson chi-square)
||||||||<25% style="TEXT-ALIGN: center"> '''Model''' ||<25% style="TEXT-ALIGN: center"> '''Chi-square''' ||<25% style="TEXT-ALIGN: center"> '''Df'''||<25% style="TEXT-ALIGN: center"> '''p-value''' ||
||||||||<25% style="VERTICAL-ALIGN: top"> Linear ||<25% style="VERTICAL-ALIGN: top"> 7.96 ||<25% style="VERTICAL-ALIGN: top"> 1 ||<25% style="VERTICAL-ALIGN: top"> 0.005 ||
||||||||<25% style="VERTICAL-ALIGN: top"> Lack of Fit ||<25% style="VERTICAL-ALIGN: top"> 0.29 ||<25% style="VERTICAL-ALIGN: top"> 1 ||<25% style="VERTICAL-ALIGN: top"> 0.130 ||
||||||||<25% style="VERTICAL-ALIGN: top"> Total ||<25% style="VERTICAL-ALIGN: top"> 8.25 ||<25% style="VERTICAL-ALIGN: top"> 2 ||<25% style="VERTICAL-ALIGN: top"> 0.004 ||
||||||||<25% style="VERTICAL-ALIGN: top"> ||<25% style="VERTICAL-ALIGN: top"> (Pearson Chi-square) ||<25% style="VERTICAL-ALIGN: top"> ||<25% style="VERTICAL-ALIGN: top"> ||

A more powerful form of chi-square specifically tests for a linear trend in proportions across groups. For example, proportion remembered correctly using a memory aid.

Example

Time 1

Time 2

Time 3

Correct

3

6

10

Incorrect

9

6

2

Does the proportion correct change linearly over time?

The chi-square testing the presence of a linear trend is outputted by SPSS CROSSTABS as the Linear-by-Linear association term. The lack of fit is the difference between the Pearson chi-square value and the linear-by-linear one.

Model

Chi-square

Df

p-value

Linear

7.96

1

0.005

Lack of Fit

0.29

1

0.130

Total

8.25

2

0.004

(Pearson Chi-square)

So there is a linear trend providing a reasonable fit.

Denoting the time points by –1,0 and 1 and regressing these on the observed

None: FAQ/ChiTrend (last edited 2013-08-28 10:47:50 by PeterWatson)