<?xml version="1.0" encoding="utf-8"?><!DOCTYPE article  PUBLIC '-//OASIS//DTD DocBook XML V4.4//EN'  'http://www.docbook.org/xml/4.4/docbookx.dtd'><article><articleinfo><title>FAQ/cis</title><revhistory><revision><revnumber>16</revnumber><date>2019-11-04 16:50:40</date><authorinitials>PeterWatson</authorinitials></revision><revision><revnumber>15</revnumber><date>2019-11-04 16:46:51</date><authorinitials>PeterWatson</authorinitials></revision><revision><revnumber>14</revnumber><date>2019-01-24 10:03:20</date><authorinitials>PeterWatson</authorinitials></revision><revision><revnumber>13</revnumber><date>2016-08-15 09:29:43</date><authorinitials>PeterWatson</authorinitials></revision><revision><revnumber>12</revnumber><date>2016-08-15 09:27:19</date><authorinitials>PeterWatson</authorinitials></revision><revision><revnumber>11</revnumber><date>2013-09-02 08:52:47</date><authorinitials>PeterWatson</authorinitials></revision><revision><revnumber>10</revnumber><date>2013-09-02 08:51:59</date><authorinitials>PeterWatson</authorinitials></revision><revision><revnumber>9</revnumber><date>2013-09-02 08:51:11</date><authorinitials>PeterWatson</authorinitials></revision><revision><revnumber>8</revnumber><date>2013-03-08 10:17:16</date><authorinitials>localhost</authorinitials><revremark>converted to 1.6 markup</revremark></revision><revision><revnumber>7</revnumber><date>2010-08-17 09:40:19</date><authorinitials>PeterWatson</authorinitials></revision><revision><revnumber>6</revnumber><date>2010-08-17 09:40:06</date><authorinitials>PeterWatson</authorinitials></revision><revision><revnumber>5</revnumber><date>2010-08-17 09:34:17</date><authorinitials>PeterWatson</authorinitials></revision><revision><revnumber>4</revnumber><date>2010-08-17 09:29:54</date><authorinitials>PeterWatson</authorinitials></revision><revision><revnumber>3</revnumber><date>2009-02-24 13:43:12</date><authorinitials>PeterWatson</authorinitials></revision><revision><revnumber>2</revnumber><date>2009-02-24 13:41:47</date><authorinitials>PeterWatson</authorinitials></revision><revision><revnumber>1</revnumber><date>2009-02-24 13:40:28</date><authorinitials>PeterWatson</authorinitials></revision></revhistory></articleinfo><section><title>A note on confidence intervals and statistical significance</title><para>If two 95% confidence intervals overlap this does <emphasis>not</emphasis> imply that the two statistics on which they are based (e.g. means, odds ratios) differ at the 5 percent level. In other words it is possible for the difference between two statistics to be statistically non-zero and for their respective confidence intervals still to overlap. This is usually the case when the difference between the means has moderate significance.  </para><para>It <emphasis>is</emphasis> true, however, that if a pair of confidence intervals do not overlap the difference between the two statistics is statistically non-zero. </para><para>The rationale behind the above discrepancy is explained in this <ulink url="https://lsr-wiki-01.mrc-cbu.cam.ac.uk/statswiki/FAQ/cis/statswiki/FAQ/cis?action=AttachFile&amp;do=get&amp;target=cis.pdf">article</ulink> taken from the Cornell University website. See also <ulink url="https://lsr-wiki-01.mrc-cbu.cam.ac.uk/statswiki/FAQ/cis/statswiki/FAQ/cis?action=AttachFile&amp;do=get&amp;target=cis2.pdf">here.</ulink> </para><para>As a special case if two independent group means have the same standard error (se) then the standard error of the difference in the two means equals sqrt(se<superscript>2 </superscript>+ se<superscript>2 </superscript>) = sqrt(2 se<superscript>2 </superscript>) = sqrt(2)se. </para><para>Now if both groups have large sample sizes then the group difference is approximately statistically significant if the abs[difference in group means] / (sqrt(2) se) is greater than 2 ie if the abs(difference in group means) &gt; 2 x sqrt(2) se = approximately 2.8 se. Now, 2.8 se is greater than 2 se which suggests that in this special case of equal mean standard errors two intervals about two statistically non-significant means could not overlap if the interval widths about the mean are equal to one standard error of each mean. </para><para>The below is taken from a reply to the psych-postgrads list: </para><para>It depends slightly on what you want to use the outcomes for. A rather simple way is to visualise the confidence intervals. If the 95%CI’s are touching, p =.01. If they are further away from each other, p &lt; .01. Cumming and Finch (2005) state that if the 95%CI arms overlap by up to half their length (so the end of one 95%CI is halfway between the end of the other one and its mean), p is approximately .05. </para><para>See the following  <ulink url="http://www.psychologicalscience.org/index.php/publications/observer/2010/april-10/understanding-confidence-intervals-cis-and-effect-size-estimation.html">link</ulink> for an explanation with some fancy pictures including a formula for working out the sample size required for a specific precision for computing means. </para><para>If you want to know more about Effect Sizes and Confidence Intervals in general, I’d recommend reading “Understanding the New Statistics” by Geoff Cumming. </para><para>Altman and Bland (2011) give simple formulae to compute a p-value from a confidence interval. </para><para><emphasis role="underline">References</emphasis> </para><para>Altman DG and Bland M (2011) <ulink url="https://www.bmj.com/content/343/bmj.d2304">How to obtain the p-value from a confidence interval.</ulink> <emphasis>BMJ</emphasis> <emphasis role="strong">343</emphasis>:d2304. </para><para>Cumming G (2012) Understanding the New Statistics: Effect sizes, confidence intervals and meta-analyses. Routledge:New York. </para><para>Cumming G and Finch S (2005) <ulink url="https://lsr-wiki-01.mrc-cbu.cam.ac.uk/statswiki/FAQ/cis/statswiki/FAQ/cis?action=AttachFile&amp;do=get&amp;target=cioverlap.pdf">Inference by eye. Confidence intervals and how to read pictures of data.</ulink> <emphasis>American Psychologist</emphasis> <emphasis role="strong">60(2)</emphasis> 170-180. </para><para>Wolfe R and Hanley J (2002) If we're so different, why do we keep overlapping? When 1 plus 1 doesn't make 2. CMAJ 166 65-66  </para></section></article>