112015-07-02 11:17:32PeterWatson102015-07-02 11:17:16PeterWatson92015-07-02 11:16:33PeterWatson82015-07-02 11:16:17PeterWatson72015-07-02 11:14:53PeterWatson62015-07-02 11:13:41PeterWatson52015-07-02 11:11:22PeterWatson42015-07-02 11:11:08PeterWatson32015-07-02 11:10:56PeterWatson22015-07-02 11:10:38PeterWatson12015-07-02 11:10:05PeterWatson

An example of one instance of 3 reps is AAAABC. There are (6 choose 2) possible positions of the two non-repeated stimuli in a sequence of length 6. These are There are 92 possible stimuli and the two stimuli must be distinct from each other and the repeated stimulus. This gives 92x91x15x90 combinations and a probability, dividing by $$926 $$ , of 0.00001. For one instance of 4 reps e.g. ABBBBB there are 6 possible positions for the non-repeated stimulus (each of the 6 positions in the sequence). There are 92 possible stimuli and the repeated and non-repeated stimuli must be different giving 92x6x91 possible combinations and a probability, dividing by $$926 $$ , of 0.00000008. There can be no more than one instance of 3, 4 or 5 reps so the above scenarios cover all the possibilities for 3 and 4 reps respectively since there is only a single instance possible of 3, 4 or 5 reps.